document.write( "Question 1062681: I have 59 coins that include pennies, nickels, dimes, and quarters. There are twice as many dimes as nickels and 3 times as many quarters as dimes. The total value of the coins is $7.23. How many of each kind of coin do I have? \n" ); document.write( "
Algebra.Com's Answer #677657 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Let n be nickels, and p be pennies. Then dimes are 2n, and quarters are 3(2n), or 6n. So: \n" ); document.write( "p+n+2n+6n=p+9n=59 \n" ); document.write( "p+5n+10(2n)+25(6n)=p+175n=723 \n" ); document.write( "p+175n=723 \n" ); document.write( "p+9n=59 \n" ); document.write( "166n=664 \n" ); document.write( "n=4 \n" ); document.write( "2n=8 \n" ); document.write( "6n=24 \n" ); document.write( "p=23 \n" ); document.write( "You have 23 pennies, 4 nickels, 8 dimes, and 24 quarters. ☺☺☺☺ \n" ); document.write( " \n" ); document.write( " |