document.write( "Question 1062536: Br resolving the forces horizontally and vertically, find the magnitude and direction of the resultant of the 4 forces shown below:\r
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document.write( "1. F1 : 10N 90 degrees from X-axis (In other words y/ direction-north)
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document.write( "2. F2 : 30N 30 degrees from X-axis (direction-NE)
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document.write( "3. F3 : 20N 10 degrees from X-axis (direction-NE)
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document.write( "4. F4 : 10N 30 degrees belowX-axis (direction-SW) \n" );
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Algebra.Com's Answer #677553 by josgarithmetic(39623)![]() ![]() ![]() You can put this solution on YOUR website! Those forces are like this:\r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "F1: 90 degrees, 10 Newtons\r\n" ); document.write( "F2: 30 degrees, 30 N\r\n" ); document.write( "F3: 10 degrees, 20 N\r\n" ); document.write( "F4: 120 degrees, 10 N\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Put them into components. \n" ); document.write( "West-East Component \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "North-South Component \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "These forces make an EASTWARD component \n" ); document.write( "Decimal Approximations: \n" ); document.write( "EASTWARD 37.017 Newtons \n" ); document.write( "NORTHWARD 23.473 Newtons \n" ); document.write( "- \n" ); document.write( "Angle Direction? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( "Magnitude? \n" ); document.write( " \n" ); document.write( " |