document.write( "Question 1062546: A workshop table has an equilateral triangular top, each side is 900mm, the legs being at the three corners. A load of 500N is placed on the table at a point distant 325mm from one leg and 625mm from another. What is the load in each of the three legs. \n" ); document.write( "
Algebra.Com's Answer #677521 by addingup(3677)![]() ![]() You can put this solution on YOUR website! height(h) of equilateral triangle: 900*sqrt(3)/2 = 450*sqrt(3) \n" ); document.write( "area of the equilateral triangle is sqrt(3)*900^2/4 = 202500*sqrt(3) \n" ); document.write( "Let the point at 325mm from one leg and 625mm from another be P. \n" ); document.write( "We draw three line segments from point P to each of the vertices of the equilateral triangle. \n" ); document.write( "Now, let V(1), V(2), V(3) be the vertices of the triangular table top, x be the length of a side, L(1), L(2), L(3) be the loads on the three legs. \n" ); document.write( "And V(1)P+V(2)P+V(3)P = x*sqrt(3) \n" ); document.write( "V(1)P = 900*sqrt(3)-325-625 \n" ); document.write( "we have all three distances from P to the vertices \n" ); document.write( "we have three triangles to consider, (V(2),P,V(3)), (V(1),V(2),P) and (V(3),P,(V(1)) \n" ); document.write( "select triangle (V(2),P,V(3)) to work with, the other two are done in a similar manner \n" ); document.write( "L(1) will be the load*ratio of the area of triangle (V(2),P,V(3)) to the area of (V(1),V(2),V(3) \n" ); document.write( "L(1) = 500*area of (V(2),P,V(3))/202500*sqrt(3) \n" ); document.write( "we can use Heron's formula to determine the area of triangle (V(2),P,V(3)) \n" ); document.write( "T = sqrt(s(s-a)(s-b)(s-x)), where s = (a+b+x)/2, a=325, b=625, x=900 \n" ); document.write( "Do L(2) and L(3) the same way. \n" ); document.write( " |