document.write( "Question 93116: How do i evaluate the following:\r
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document.write( "log3 81
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document.write( "log4 256
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document.write( "log2 (1/32)
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document.write( "log5 1
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document.write( "log3 (-1)\r
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document.write( "Please help
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document.write( "thanks
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document.write( "Lucy \n" );
document.write( "
Algebra.Com's Answer #67750 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How do i evaluate the following? \n" ); document.write( "Comment: log is just another name for \"exponent\" or \"power\" \n" ); document.write( "-------------- \n" ); document.write( "log3 81 \n" ); document.write( "Let the answer be \"x\" \n" ); document.write( "Then x= log3 81 \n" ); document.write( "So x is the exponent of 3 that gives you 81 \n" ); document.write( "3^x = 81 \n" ); document.write( "3^x = 3^4 \n" ); document.write( "x=4 \n" ); document.write( "log3 81 = 4\r \n" ); document.write( "\n" ); document.write( "--------------------- \n" ); document.write( "log4 256 \n" ); document.write( "Similarly \n" ); document.write( "x = log4 256 \n" ); document.write( "4^x = 256 \n" ); document.write( "4^x = 4^4 \n" ); document.write( "x = 4 \n" ); document.write( "-------------- \n" ); document.write( "log2 (1/32) \n" ); document.write( "2^x = (1/32) \n" ); document.write( "2^x = 2^-5 \n" ); document.write( "x = -5 \n" ); document.write( "--------------- \n" ); document.write( "log5 1 \n" ); document.write( "5^x = 1 \n" ); document.write( "5^x = 5^0 \n" ); document.write( "x=0 \n" ); document.write( "------------- \n" ); document.write( "log3 (-1) \n" ); document.write( "3^x = -1 \n" ); document.write( "No such x exists. \n" ); document.write( "No solution. \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------------- \n" ); document.write( " |