document.write( "Question 93105: Choose the one alternative that best completes the statement or answers the question. \r
\n" ); document.write( "\n" ); document.write( "Solve by completing the square.
\n" ); document.write( "x^2 - 6x - 40 = 0 \r
\n" ); document.write( "\n" ); document.write( "a) 10, -4 b) -10, 4 c)(-36, -4 d) square root of -40, negative square root of -40 \r
\n" ); document.write( "\n" ); document.write( "I think the answer is d after I plugged in all the options, but I don't know how to prove it. When I try to use completing the square I get up to this point, 6 plus or minus the square root of 160 over 2 and I can't go any further. Thanks so much!!
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Algebra.Com's Answer #67747 by tutorcecilia(2152)\"\" \"About 
You can put this solution on YOUR website!
x^2 - 6x - 40+40 =40
\n" ); document.write( "x^2-6x=40
\n" ); document.write( "\"%28x%5E2-6x%2B%286%2F2%29%5E2%29\"}=\"%2840%2B%286%2F2%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "\"%28x%5E2-6x%2B%283%29%5E2%29\"=\"%2840%2B%283%29%5E2%29\"
\n" ); document.write( "\"%28x%5E2-6x%2B%283%29%5E2%29\"= \"%2840%2B%289%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-6x%2B%283%29%5E2%29\"=49
\n" ); document.write( "\"%28x-3%29%28x-3%29%29\"=49 [factor]
\n" ); document.write( "\"%28x-3%29%5E2%29\"= 49\r
\n" ); document.write( "\n" ); document.write( "\"%28sqrt%28%28x-3%29%5E2%29%29%29\"= \"%28sqrt%28+49%29%29\"
\n" ); document.write( "x-3=+-7
\n" ); document.write( "x=3+-7
\n" ); document.write( "x=3+7=10
\n" ); document.write( "or
\n" ); document.write( "x=3-7=-4
\n" ); document.write( ".
\n" ); document.write( "Solution: (10 or -4)
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