document.write( "Question 1062527: In 10 years A will be twice as old as B was 10 years ago. If A is now 9 years older than B then the present age of B is? \n" ); document.write( "
Algebra.Com's Answer #677466 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "In 10 years A will be twice as old as B was 10 years ago. If A is now 9 years older than B then the present age of B is?
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document.write( "The condition says:\r\n" );
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document.write( "A + 10 = 2*(B-10),     (1)    (\"In 10 years A will be twice as old as B was 10 years ago.\")\r\n" );
document.write( "A = B + 9.             (2)    (\" A is now 9 years older than B:)\r\n" );
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document.write( "From (2), substitute the expression A = B + 9 into (1), replacing A. You will get\r\n" );
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document.write( "(B+9) + 10 = 2(B-10),\r\n" );
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document.write( "B + 19 = 2B - 20  --->  19 + 20 = B.\r\n" );
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document.write( "Hence, B is 39 years old now.\r\n" );
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document.write( "Then A = B + 9 = 39 + 9 = 48 years old now.\r\n" );
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\n" ); document.write( "\n" ); document.write( "There is a bunch of lessons on age word problems \r
\n" ); document.write( "\n" ); document.write( "    - Age problems and their solutions\r
\n" ); document.write( "\n" ); document.write( "    - A fresh formulation of a traditional age problem\r
\n" ); document.write( "\n" ); document.write( "    - Really intricate age word problem\r
\n" ); document.write( "\n" ); document.write( "    - Selected age word problems from the archive\r
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\n" ); document.write( "\n" ); document.write( "Read them and become an expert in solving age problems.\r
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\n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this online textbook under the topic \"Age word problems\".\r
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