document.write( "Question 1062471: Jasmine is nw half as old as her father.12 years ao, the father was 3 times as old as jasmine.find their ages.
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Algebra.Com's Answer #677450 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "Jasmine is \"highlight%28cross%28nw%29%29\" now half as old as her father. 12 years \"highlight%28cross%28ao%29%29\" ago, the father was 3 times as old as jasmine.find their ages.
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document.write( "F = 2J,              (1)   (\"Jasmine is now half as old as her father\")\r\n" );
document.write( "F - 12 = 3(J-12).    (2)   (\"12 years ago . . .\")\r\n" );
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document.write( "From (1), substitute F = 2J into (2) replacing F. You will get the single equation for J:\r\n" );
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document.write( "2J - 12 = 3(J-12)  --->  2J - 12 = 3J - 36  --->  J = 36 - 12 = 24.\r\n" );
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document.write( "Answer.  Jasmin is 24 years old now. The father is 2*J = 2*24 = 48 years old now.\r\n" );
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\n" ); document.write( "\n" ); document.write( "There is a bunch of lessons on age word problems \r
\n" ); document.write( "\n" ); document.write( "    - Age problems and their solutions\r
\n" ); document.write( "\n" ); document.write( "    - A fresh formulation of a traditional age problem\r
\n" ); document.write( "\n" ); document.write( "    - Really intricate age word problem\r
\n" ); document.write( "\n" ); document.write( "    - Selected age word problems from the archive\r
\n" ); document.write( "\n" ); document.write( "    - Age problem for the day of April, 1 \r
\n" ); document.write( "\n" ); document.write( "    - OVERVIEW of lessons on age problems\r
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\n" ); document.write( "\n" ); document.write( "Read them and become an expert in solving age problems.\r
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\n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this online textbook under the topic \"Age word problems\".\r
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