document.write( "Question 93107: Write an equation for the linear function f satisfying the given conditions. \r
\n" ); document.write( "\n" ); document.write( "f(3) = 4 and f(0) = 9
\n" ); document.write( "I know that these would be looked at as (3,4) and (0,9), but I don't know what type of \"equation\" they're looking for. Thanks so much!!
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Algebra.Com's Answer #67744 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Since it is a \"linear\" function, they are looking for an equation in the form of \"y=mx%2Bb\" which forms a line. So we have the points (3,4) and (0,9). Lets find the equation through those points\r
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\n" ); document.write( "\n" ); document.write( "First lets find the slope through the points (\"3\",\"4\") and (\"0\",\"9\")\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"m=%289-4%29%2F%280-3%29\" Plug in \"y%5B2%5D=9\",\"y%5B1%5D=4\",\"x%5B2%5D=0\",\"x%5B1%5D=3\" (these are the coordinates of given points)\r
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\n" ); document.write( "\n" ); document.write( "\"m=+5%2F-3\" Subtract the terms in the numerator \"9-4\" to get \"5\". Subtract the terms in the denominator \"0-3\" to get \"-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=-5%2F3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the slope is\r
\n" ); document.write( "\n" ); document.write( "\"m=-5%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point-slope formula to find the equation of the line:\r
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\n" ); document.write( "\n" ); document.write( "------Point-Slope Formula------
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is one of the given points\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-4=%28-5%2F3%29%28x-3%29\" Plug in \"m=-5%2F3\", \"x%5B1%5D=3\", and \"y%5B1%5D=4\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-4=%28-5%2F3%29x%2B%28-5%2F3%29%28-3%29\" Distribute \"-5%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-4=%28-5%2F3%29x%2B5\" Multiply \"-5%2F3\" and \"-3\" to get \"15%2F3\". Now reduce \"15%2F3\" to get \"5\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-5%2F3%29x%2B5%2B4\" Add \"4\" to both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-5%2F3%29x%2B9\" Combine like terms \"5\" and \"4\" to get \"9\" \r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line which goes through the points (\"3\",\"4\") and (\"0\",\"9\") is:\"y=%28-5%2F3%29x%2B9\"\r
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\n" ); document.write( "\n" ); document.write( "The equation is now in \"y=mx%2Bb\" form (which is slope-intercept form) where the slope is \"m=-5%2F3\" and the y-intercept is \"b=9\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=%28-5%2F3%29x%2B9\" and plot the points (\"3\",\"4\") and (\"0\",\"9\"), we get this: (note: if you need help with graphing, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%28-5%2F3%29x%2B9\" through the points (\"3\",\"4\") and (\"0\",\"9\")\r
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\n" ); document.write( "\n" ); document.write( "Since the equation is \"y=%28-5%2F3%29x%2B9\" the function is \"f%28x%29=%28-5%2F3%29x%2B9\" (just replace y with f(x))
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