.
\n" );
document.write( "\r\n" );
document.write( "That's a sine graph shifted left from the origin (0,0)\r\n" );
document.write( "to the first x-intercept left of the x-axis.\r\n" );
document.write( "\r\n" );
document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "Since the highest it goes in 2, and the lowest it goes is\r\n" );
document.write( "-2, the amplitude, a, is 2.\r\n" );
document.write( "So we have so far:\r\n" );
document.write( "\r\n" );
document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "The period is given by the formula
\r\n" );
document.write( "\r\n" );
document.write( "Each mark on the x-axis represents π because there\r\n" );
document.write( "are 6 of them and the 6π at the right end of the graph\r\n" );
document.write( "lets us know that each mark counts as π.\r\n" );
document.write( "\r\n" );
document.write( "We can tell the period because it's the distance along\r\n" );
document.write( "the x-axis from 1 peak to the next.\r\n" );
document.write( "\r\n" );
document.write( "The peak marked (-π/2,2) has x-coordinate -π/2 and the\r\n" );
document.write( "next peak is halfway between 3π and 4π which is
, \r\n" );
document.write( "or
or
. So the period is the \r\n" );
document.write( "difference of these two x-values, which is \r\n" );
document.write( "



\r\n" );
document.write( "\r\n" );
document.write( "Since the period is given by the formula
, we have\r\n" );
document.write( "the equation: \r\n" );
document.write( "\r\n" );
document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "Multiply both sides by b\r\n" );
document.write( "\r\n" );
document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "Divide both sides by 4π\r\n" );
document.write( "\r\n" );
document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "Cancel the π's:\r\n" );
document.write( "\r\n" );
document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "So we have so far:\r\n" );
document.write( "\r\n" );
document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "Finally we need to know the phase shift which is
,\r\n" );
document.write( "right if it's negative and left if it's positive.\r\n" );
document.write( "\r\n" );
document.write( "The first x-intercept left of the origin is halfway\r\n" );
document.write( "between -π and -2π which is
, \r\n" );
document.write( "or
or
. \r\n" );
document.write( "\r\n" );
document.write( "So c = that with a positive sign since it shifts left from (0,0,)\r\n" );
document.write( "\r\n" );
document.write( "





\r\n" );
document.write( "\r\n" );
document.write( "So the final answer is\r\n" );
document.write( "\r\n" );
document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" );
document.write( "