document.write( "Question 1062508: Please help me find \"+a+\", \"+b+\" & \"+c+\" for the function
\n" ); document.write( "\"f%28x%29\"\"%22%22=%22%22\"\"a%2Asin%28bx%2Bc%29\". The graph of \"+f+\" must match this
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Algebra.Com's Answer #677430 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "That's a sine graph shifted left from the origin (0,0)\r\n" );
document.write( "to the first x-intercept left of the x-axis.\r\n" );
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document.write( "\"f%28x%29\"\"%22%22=%22%22\"\"a%2Asin%28bx%2Bc%29\"\r\n" );
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document.write( "Since the highest it goes in 2, and the lowest it goes is\r\n" );
document.write( "-2, the amplitude, a, is 2.\r\n" );
document.write( "So we have so far:\r\n" );
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document.write( "\"f%28x%29\"\"%22%22=%22%22\"\"2%2Asin%28bx%2Bc%29\"\r\n" );
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document.write( "The period is given by the formula \"2pi%2Fb\"\r\n" );
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document.write( "Each mark on the x-axis represents π because there\r\n" );
document.write( "are 6 of them and the 6π at the right end of the graph\r\n" );
document.write( "lets us know that each mark counts as π.\r\n" );
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document.write( "We can tell the period because it's the distance along\r\n" );
document.write( "the x-axis from 1 peak to the next.\r\n" );
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document.write( "The peak marked (-π/2,2) has x-coordinate -π/2 and the\r\n" );
document.write( "next peak is halfway between 3π and 4π which is \"3%261%2F2pi\", \r\n" );
document.write( "or \"expr%287%2F2%29pi\" or \"%287pi%29%2F2\". So the period is the \r\n" );
document.write( "difference of these two x-values, which is \r\n" );
document.write( "\"%287pi%29%2F2-%28-pi%2F2%29\"\"%22%22=%22%22\"\"8pi%2F2\"\"%22%22=%22%22\"\"4pi\"\r\n" );
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document.write( "Since the period is given by the formula \"2pi%2Fb\", we have\r\n" );
document.write( "the equation:  \r\n" );
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document.write( "\"2pi%2Fb\"\"%22%22=%22%22\"\"4pi\"\r\n" );
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document.write( "Multiply both sides by b\r\n" );
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document.write( "\"2pi\"\"%22%22=%22%22\"\"4pi%2Ab\"\r\n" );
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document.write( "Divide both sides by 4π\r\n" );
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document.write( "\"2pi%2F%284pi%29\"\"%22%22=%22%22\"\"b\"\r\n" );
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document.write( "Cancel the π's:\r\n" );
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document.write( "\"2%2F4\"\"%22%22=%22%22\"\"b\"\r\n" );
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document.write( "\"1%2F2\"\"%22%22=%22%22\"\"b\"\r\n" );
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document.write( "So we have so far:\r\n" );
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document.write( "\"f%28x%29\"\"%22%22=%22%22\"\"2%2Asin%28expr%281%2F2%29%2Ax%2Bc%29\"\r\n" );
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document.write( "Finally we need to know the phase shift which is \"c%2Fb\",\r\n" );
document.write( "right if it's negative and left if it's positive.\r\n" );
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document.write( "The first x-intercept left of the origin is halfway\r\n" );
document.write( "between -π and -2π which is \"-1%261%2F2pi\", \r\n" );
document.write( "or \"expr%28-3%2F2%29pi\" or \"-%283pi%29%2F2\". \r\n" );
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document.write( "So c = that with a positive sign since it shifts left from (0,0,)\r\n" );
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document.write( "\"c%2Fb\"\"%22%22=%22%22\"\"%28%283pi%29%2F2%29%2F2\"\"%22%22=%22%22\"\"%28%283pi%29%2F2%29%2A%281%2F2%29\"\"%22%22=%22%22\"\"3pi%2F4\"\r\n" );
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document.write( "So the final answer is\r\n" );
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document.write( "\"f%28x%29\"\"%22%22=%22%22\"\"2%2Asin%28expr%281%2F2%29%2Ax%2B3pi%2F4%29\"\r\n" );
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document.write( "Edwin
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