document.write( "Question 1062474: The area of a square is decreased by 80%. By what percent did the perimeter decrease? \n" ); document.write( "
Algebra.Com's Answer #677388 by Alan3354(69443)\"\" \"About 
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The area of a square is decreased by 80%. By what percent did the perimeter decrease?
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\n" ); document.write( "After decrease area = 0.2 of the original.
\n" ); document.write( "Area After/Area Before = 0.2
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\n" ); document.write( "Area = s^2
\n" ); document.write( "After s^2/Before s^2 = 0.2
\n" ); document.write( "After s/Before x = sqrt(0.2) =~ 0.447 = 44/7%
\n" ); document.write( "Side Decrease = 100 - 44.7 = 55.3%
\n" ); document.write( "Perimeter decrease = 55.3%\r
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