document.write( "Question 1062474: The area of a square is decreased by 80%. By what percent did the perimeter decrease? \n" ); document.write( "
Algebra.Com's Answer #677388 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The area of a square is decreased by 80%. By what percent did the perimeter decrease? \n" ); document.write( "-------- \n" ); document.write( "After decrease area = 0.2 of the original. \n" ); document.write( "Area After/Area Before = 0.2 \n" ); document.write( "----- \n" ); document.write( "Area = s^2 \n" ); document.write( "After s^2/Before s^2 = 0.2 \n" ); document.write( "After s/Before x = sqrt(0.2) =~ 0.447 = 44/7% \n" ); document.write( "Side Decrease = 100 - 44.7 = 55.3% \n" ); document.write( "Perimeter decrease = 55.3%\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |