document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=93102>Question 93102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3Y=X+5 3X-9Y= -10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67734 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are several methods for solving this system of equations.  I will use the method of addition:<BR>\n" );
document.write( "First, line-up the variables:<BR>\n" );
document.write( "-x+3y=5 <BR>\n" );
document.write( "3x-9y=-10\r<BR>\n" );
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document.write( ".Next, multiply one of the equations by a number that will cause a variable to cancel out:<BR>\n" );
document.write( "3(-x+3y=5)=-3x+9y=15<BR>\n" );
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document.write( "Add the equations together:<BR>\n" );
document.write( "-3x+9y=15<BR>\n" );
document.write( "3x-9y=-10<BR>\n" );
document.write( "___________<BR>\n" );
document.write( "0=-5 (incorrect answer, therefore, there is \"no solution\"]  </SPAN>\n" );
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