document.write( "Question 1062413: If second number is 20% greater than first number, then by how much percent second number is less than first number? \n" ); document.write( "

Algebra.Com's Answer #677329 by KMST(5328) $\"\"$ $\"About$

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The second number, $\"n%5B2%5D\"$ , is
\n" ); document.write( " $\"%22100%25%22%2B%2220%25%22=%22120%25%22=120%2F100=6%2F5=1.2\"$ times the first number, $\"n%5B1%5D%7D%7D+.%0D%0ASo%2C+%7B%7B%7Bn%5B2%5D=1.2%2An%5B1%5D=%285%2F6%29%2An%5B1%5D\"$
\n" ); document.write( " $\"n%5B1%5D=n%5B2%5D%2F1.2=n%5B2%5D%2F%28%286%2F5%29%29=%285%2F6%29%2An%5B2%5D\"$
\n" ); document.write( "That tells you that $\"n%5B1%5D\"$ is less than $\"n%5B2%5D\"$ by a difference of
\n" ); document.write( " $\"n%5B2%5D-n%5B1%5D=%281%2F6%29n%5B2%5D=%22about0.1667%22%2An%5B2%5D\"$ .
\n" ); document.write( "As a fraction or percentage of $\"n%5B2%5D\"$ ,
\n" ); document.write( "the first number, $\"n%5B1%5D\"$ , is less than the second number, $\"n%5B2%5D\"$ , by
\n" ); document.write( " $\"1%2F6=%28%281%2F6%29%29%2F100=100%2F6\"$ $\"%22%25%22=16%262%2F3\"$ $\"%22%25%22\"$ .
\n" ); document.write( "If you want the percentage as a decimal,
\n" ); document.write( "you will have to be content with an approximate number.
\n" ); document.write( " $\"0.1667=16.67%2F100=%2216.67%25%22\"$ . \n" ); document.write( "

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