document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1062412>Question 1062412</A>: <I><SPAN STYLE=\"word-break: break-all;\"> who+many+briks+each+of+size+23cm+11.5+cm+8+cm+will+be+required+to+build+a+wall+of+size+11.5+meter+into+2.3+meter+into+40+cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #677321 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=677321\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8 cm fits 40/8=5 times into 40 cm.<BR>\n" );
document.write( "11.5 cm fits 1150/11.5=100 times into 11.5m=1150cm.<BR>\n" );
document.write( "23 cm fits 230/23=10 times into 2.3m=230cm.<BR>\n" );
document.write( "Used that way,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2A100%2A10=5000 ALIGN=MIDDLE  ALT=\"5%2A100%2A10=5000\"   DISABLED_style= \"max-width:90%; height:auto;\" > bricks would be used. </SPAN>\n" );
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