document.write( "Question 93090: I am not good at all with word problems and needs help\r
\n" ); document.write( "\n" ); document.write( "A rectangle garden is to be surrounded by a walkway of constant width. The gardens dimensions are 30 ft by 40 ft. The total area, garden plus walkway, is to be 1800 ft^2
\n" ); document.write( "What must be the width of the walkway to the nearest thousandth?\r
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Algebra.Com's Answer #67728 by checkley75(3666) $\"\"$ $\"About$

You can put this solution on YOUR website!
30*40=1200 area of the garden.
\n" ); document.write( "1800=(30+2w)(40+2w) these are the dimentions of the garden plus the walk way.
\n" ); document.write( "1800=1200+80x+60w+4w^2
\n" ); document.write( "4w62+140w+1200-1800=0
\n" ); document.write( "4w^2+140w-600=0
\n" ); document.write( "4(w^2+35w-150)=0
\n" ); document.write( "using the quadratic equaton we get:
\n" ); document.write( " $\"w=%28-b%2B-sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"$
\n" ); document.write( "w=(-35+-sqrt[35^2-4*1*-150])/2*1
\n" ); document.write( "w=-35+-sqrt[1225+600])/2
\n" ); document.write( "w=(-35+-sqrt1825)/2
\n" ); document.write( "w=(-35+-42.72)/2
\n" ); document.write( "w=(-35+42.72)/2
\n" ); document.write( "w=7.72/2
\n" ); document.write( "w=3.86 ft. is the width of the walkway\r
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