document.write( "Question 1062390: Hello everyone, and Merry Christmas!!
\n" ); document.write( "Can somebody explain me the difference about these two kind of solutions
\n" ); document.write( "starting from following equation:
\n" ); document.write( "sin(x)cos(x) + cos^2(x) = 0
\n" ); document.write( "a) first method dividing by cos^2(x) I become tan(x) + 1 = 0 wich gives me
\n" ); document.write( " the result: tan(x) = -1; x= -PI/4 + nPI; n€Z
\n" ); document.write( "b) second method dividing by sin^2(x) I become cot(x) + cot^2(x) = 0 wich gives
\n" ); document.write( " me the two results: cot(x) = -1; x= -PI/4 + nPI; n€Z
\n" ); document.write( " cot(x) = 0; x= PI/2 + nPI; n€Z
\n" ); document.write( "Where am I doing or thinking wrong? Thank you very much RB
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Algebra.Com's Answer #677270 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
sin(x)cos(x) + cos^2(x) = 0
\n" ); document.write( "a) first method dividing by cos^2(x) I become tan(x) + 1 = 0 wich gives me
\n" ); document.write( " the result: tan(x) = -1; x= -PI/4 + nPI; n€Z
\n" ); document.write( "b) second method dividing by sin^2(x) I become cot(x) + cot^2(x) = 0 wich gives
\n" ); document.write( " me the two results: cot(x) = -1; x= -PI/4 + nPI; n€Z
\n" ); document.write( " cot(x) = 0; x= PI/2 + nPI; n€Z
\n" ); document.write( "Where am I doing or thinking wrong? Thank you very much RB
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\n" ); document.write( "sin(x)cos(x) + cos^2(x) = 0
\n" ); document.write( "cos*(sin + cos) = 0
\n" ); document.write( "cos = 0
\n" ); document.write( "x = pi/2 + n*pi, n = any integer
\n" ); document.write( "---------------
\n" ); document.write( "sin + cos = 0
\n" ); document.write( "tan + 1 = 0
\n" ); document.write( "tan = -1
\n" ); document.write( "x = 3pi/4, 7pi/4 + n*pi, n = any integer\r
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