document.write( "Question 1062390: Hello everyone, and Merry Christmas!!
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document.write( "Can somebody explain me the difference about these two kind of solutions
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document.write( "starting from following equation:
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document.write( "sin(x)cos(x) + cos^2(x) = 0
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document.write( "a) first method dividing by cos^2(x) I become tan(x) + 1 = 0 wich gives me
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document.write( " the result: tan(x) = -1; x= -PI/4 + nPI; n€Z
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document.write( "b) second method dividing by sin^2(x) I become cot(x) + cot^2(x) = 0 wich gives
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document.write( " me the two results: cot(x) = -1; x= -PI/4 + nPI; n€Z
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document.write( " cot(x) = 0; x= PI/2 + nPI; n€Z
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document.write( "Where am I doing or thinking wrong? Thank you very much RB
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Algebra.Com's Answer #677270 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! sin(x)cos(x) + cos^2(x) = 0 \n" ); document.write( "a) first method dividing by cos^2(x) I become tan(x) + 1 = 0 wich gives me \n" ); document.write( " the result: tan(x) = -1; x= -PI/4 + nPI; n€Z \n" ); document.write( "b) second method dividing by sin^2(x) I become cot(x) + cot^2(x) = 0 wich gives \n" ); document.write( " me the two results: cot(x) = -1; x= -PI/4 + nPI; n€Z \n" ); document.write( " cot(x) = 0; x= PI/2 + nPI; n€Z \n" ); document.write( "Where am I doing or thinking wrong? Thank you very much RB \n" ); document.write( "----------- \n" ); document.write( "----------- \n" ); document.write( "sin(x)cos(x) + cos^2(x) = 0 \n" ); document.write( "cos*(sin + cos) = 0 \n" ); document.write( "cos = 0 \n" ); document.write( "x = pi/2 + n*pi, n = any integer \n" ); document.write( "--------------- \n" ); document.write( "sin + cos = 0 \n" ); document.write( "tan + 1 = 0 \n" ); document.write( "tan = -1 \n" ); document.write( "x = 3pi/4, 7pi/4 + n*pi, n = any integer\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |