document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1062384>Question 1062384</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two complimentary angles are drawn such that one angle is 10° more than seven times the other angle. find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #677266 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=677266\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two complimentary [sic] angles are drawn such that one angle is 10° more than seven times the other angle. find the measure of each angle.<BR>\n" );
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document.write( "A = angle<BR>\n" );
document.write( "B = other angle<BR>\n" );
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document.write( "A + B = 90  -- Complementary<BR>\n" );
document.write( "A = 7B + 10<BR>\n" );
document.write( "7B+10 + B = 90<BR>\n" );
document.write( "8B = 80<BR>\n" );
document.write( "B = 10<BR>\n" );
document.write( "A = 80<BR>\n" );
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