document.write( "Question 1062359: The system of equations I need to solve is:
\n" ); document.write( "7x - 8y = 24
\n" ); document.write( "xy^2 = 1\r
\n" ); document.write( "\n" ); document.write( "In the second, it's not (xy)^2, but just the y is squared. I get to substitution and replace y in the second equation with y = (7/8)x + 3 and end up with (23/32)x^3 + (21/4)x^2 + 9x - 1 = 0. My professor warned that this problem is pure evil and said at this point I would need to use rational root theorem and that there IS a rational root. Issue is I don't know how to find a rational root from a fraction as a leading coefficient (23/32).... Unless I screwed up before that and that's not what I'm looking at. \r
\n" ); document.write( "\n" ); document.write( "Any help to get me beyond this point will be greatly appreciated.
\n" ); document.write( "

Algebra.Com's Answer #677260 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
The system of equations I need to solve is:
\n" ); document.write( "7x - 8y = 24
\n" ); document.write( "xy^2 = 1\r
\n" ); document.write( "\n" ); document.write( "In the second, it's not (xy)^2, but just the y is squared. I get to substitution and replace y in the second equation with y = (7/8)x + 3 and end up with (23/32)x^3 + (21/4)x^2 + 9x - 1 = 0. My professor warned that this problem is pure evil and said at this point I would need to use rational root theorem and that there IS a rational root. Issue is I don't know how to find a rational root from a fraction as a leading coefficient (23/32).... Unless I screwed up before that and that's not what I'm looking at. \r
\n" ); document.write( "\n" ); document.write( "Any help to get me beyond this point will be greatly appreciated.
\n" ); document.write( "
It's not that bad as your professor professed.
\n" ); document.write( "\"xy%5E2+=+1\" ------- eq (ii) ==========> You got up to this point
\n" ); document.write( "You have: \"%287%2F8%29x+%2B+3\", but it should be: \"matrix%281%2C7%2C+%287%2F8%29x+-+3%2C+which%2C+is%2C+the%2C+same%2C+as%2C+7x%2F8+-+3%29\"
\n" ); document.write( "\"x%287x%2F8+-+3%29%5E2+=+1\" ----- Substituting \"7x%2F8+-+3\" for y in eq (ii)
\n" ); document.write( "\"x%2849x%5E2%2F64+-+2%2821x%2F8%29+%2B+9%29+=+1\" ----- FOILing \"%287x%2F8+-+3%29%5E2\"
\n" ); document.write( "\"x%2849x%5E2%2F64+-+42x%2F8+%2B+9%29+=+1\"
\n" ); document.write( "\"x%28%2849x%5E2+-+336x+%2B+576%29%2F64%29+=+1\" ---- Multiplying TRINOMIAL in parentheses by LCD, 64
\n" ); document.write( "\"x%2849x%5E2+-+336x+%2B+576%29+=+64\" ------ Cross-multiplying
\n" ); document.write( "\"49x%5E3+-+336x%5E2+%2B+576x+=+64\" ------- Distributing left-side
\n" ); document.write( "\"49x%5E3+-+336x%5E2+%2B+576x+-+64+=+0\" ---- Subtracting 64 from each side
\n" ); document.write( "Now is the time you use the rational root theorem with factors of 49 or 64. You will find that 4 is a root, so: x = 4, and x - 4 is a factor.\r
\n" ); document.write( "\n" ); document.write( "Using the factor x - 4, and SYNTHETIC DIVISION or LONG DIVISION of POLYNOMIALS, you will find that the QUOTIENT when \"49x%5E3+-+336x%5E2+%2B+576x+-+64\" is divided by x - 4 is: \"49x%5E2+-+140x+%2B+16\".
\n" ); document.write( "Therefore, the factors of \"49x%5E3+-+336x%5E2+%2B+576x+-+64\" are \"%28x-+4%29%2849x%5E2+-+140x+%2B+16%29\".
\n" ); document.write( "You just need to use the quadratic equation formula or COMPLETING THE SQUARE to get the final 2 factors of \"49x%5E2+-+140x+%2B+16\", which happen to be REAL also (2.73787877 and 0.1193).
\n" ); document.write( "You have 3 values for x, so substitute each one into the SIMPLER original equation [eq (i) or (ii)] to find each CORRESPONDING y-value. \r
\n" ); document.write( "\n" ); document.write( "That's it!! The trick here is to do things in STEPS, or LITTLE by LITTLE. That way, you won't be confused and make mistakes. \n" ); document.write( "
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