document.write( "Question 1062362: a pizzeria sells three sizes of pizza: small, medium, and large. the pizzas sell for $9, $10, and $13, respectively. one evening they sold 21 pizzas and received $220. if they sold 1 more medium than large pizzas, how many of each size did they sell?
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document.write( "Use the Gaussian elimination method with back substitution to solve the given word problem \n" );
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Algebra.Com's Answer #677258 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! small=x \n" ); document.write( "medium=y \n" ); document.write( "large=z\r \n" ); document.write( "\n" ); document.write( "x+y+z=21 \n" ); document.write( "9x+10y+13z=220 \n" ); document.write( "y=z+1 \n" ); document.write( "------------------ \n" ); document.write( "x+y+z=21 \n" ); document.write( "9x+10y+13z=220 \n" ); document.write( "y-z=1 \n" ); document.write( "---------------- \n" ); document.write( "first times -9 and add it to second\r \n" ); document.write( "\n" ); document.write( "9x+10y+13z=220 \n" ); document.write( "-9x-9y-9z=-189 \n" ); document.write( "y-z=1\r \n" ); document.write( "\n" ); document.write( "y+4z=31 \n" ); document.write( "y-z=1 \n" ); document.write( "-------------- \n" ); document.write( "multiply the third one by -1 and add to second \n" ); document.write( "y+4z=31 \n" ); document.write( "-y+z=-1 \n" ); document.write( "5z=30 \n" ); document.write( "z=6 \n" ); document.write( "y=z+1 \n" ); document.write( "y=7 \n" ); document.write( "x+y+z=21, x=8 \n" ); document.write( "{8,7,6} \n" ); document.write( "8*$9=$72 \n" ); document.write( "7*$10=$70 \n" ); document.write( "6*$13=$78 \n" ); document.write( "Total=21 and $220\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |