document.write( "Question 1062362: a pizzeria sells three sizes of pizza: small, medium, and large. the pizzas sell for $9, $10, and $13, respectively. one evening they sold 21 pizzas and received $220. if they sold 1 more medium than large pizzas, how many of each size did they sell?
\n" ); document.write( "Use the Gaussian elimination method with back substitution to solve the given word problem
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Algebra.Com's Answer #677258 by Boreal(15235)\"\" \"About 
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small=x
\n" ); document.write( "medium=y
\n" ); document.write( "large=z\r
\n" ); document.write( "\n" ); document.write( "x+y+z=21
\n" ); document.write( "9x+10y+13z=220
\n" ); document.write( "y=z+1
\n" ); document.write( "------------------
\n" ); document.write( "x+y+z=21
\n" ); document.write( "9x+10y+13z=220
\n" ); document.write( "y-z=1
\n" ); document.write( "----------------
\n" ); document.write( "first times -9 and add it to second\r
\n" ); document.write( "\n" ); document.write( "9x+10y+13z=220
\n" ); document.write( "-9x-9y-9z=-189
\n" ); document.write( "y-z=1\r
\n" ); document.write( "\n" ); document.write( "y+4z=31
\n" ); document.write( "y-z=1
\n" ); document.write( "--------------
\n" ); document.write( "multiply the third one by -1 and add to second
\n" ); document.write( "y+4z=31
\n" ); document.write( "-y+z=-1
\n" ); document.write( "5z=30
\n" ); document.write( "z=6
\n" ); document.write( "y=z+1
\n" ); document.write( "y=7
\n" ); document.write( "x+y+z=21, x=8
\n" ); document.write( "{8,7,6}
\n" ); document.write( "8*$9=$72
\n" ); document.write( "7*$10=$70
\n" ); document.write( "6*$13=$78
\n" ); document.write( "Total=21 and $220\r
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