document.write( "Question 1062359: The system of equations I need to solve is:
\n" ); document.write( "7x - 8y = 24
\n" ); document.write( "xy^2 = 1\r
\n" ); document.write( "\n" ); document.write( "In the second, it's not (xy)^2, but just the y is squared. I get to substitution and replace y in the second equation with y = (7/8)x + 3 and end up with (23/32)x^3 + (21/4)x^2 + 9x - 1 = 0. My professor warned that this problem is pure evil and said at this point I would need to use rational root theorem and that there IS a rational root. Issue is I don't know how to find a rational root from a fraction as a leading coefficient (23/32).... Unless I screwed up before that and that's not what I'm looking at. \r
\n" ); document.write( "\n" ); document.write( "Any help to get me beyond this point will be greatly appreciated.
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Algebra.Com's Answer #677253 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
The system of equations I need to solve is:
\n" ); document.write( "7x - 8y = 24
\n" ); document.write( "xy^2 = 1
\n" ); document.write( "In the second, it's not (xy)^2, but just the y is squared. I get to substitution and replace y in the second equation with y = (7/8)x + 3 and end up with (23/32)x^3 + (21/4)x^2 + 9x - 1 = 0.
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\n" ); document.write( "7x - 8y = 24 --> y = (7/8)x -3 *** not +3
\n" ); document.write( "x*(7x/8 - 3)^2 - 1 = 0
\n" ); document.write( "x*(49x^2/64 - 21x/32 + 9) -1 = 0
\n" ); document.write( "49x^3/64 - 21x^2/32 + 9x - 1 = 0
\n" ); document.write( "Multiply by 64
\n" ); document.write( "49x^3 - 42x^2 + 576x - 64 = 0
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\n" ); document.write( "The only real root I see is ~ 0.111905 (by graphing)\r
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