document.write( "Question 1062309: Hello there. I have been wondering how to do this question all day, you see algebra is not my strongest point and I was hoping if you could help me.\r
\n" ); document.write( "\n" ); document.write( "Here is the question\r
\n" ); document.write( "\n" ); document.write( "Look at these simultaneous questions.
\n" ); document.write( "a+b+c=10
\n" ); document.write( "a+b-c=3\r
\n" ); document.write( "\n" ); document.write( "Find the value of a+b+3c\r
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\n" ); document.write( "\n" ); document.write( "Thank you very much.
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Algebra.Com's Answer #677219 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
Hello there. I have been wondering how to do this question all day, you see algebra is not my strongest point and I was hoping if you could help me.\r
\n" ); document.write( "\n" ); document.write( "Here is the question\r
\n" ); document.write( "\n" ); document.write( "Look at these simultaneous questions.
\n" ); document.write( "a+b+c=10
\n" ); document.write( "a+b-c=3\r
\n" ); document.write( "\n" ); document.write( "Find the value of a+b+3c\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Thank you very much.
\n" ); document.write( "
a + b + c = 10 -------- eq (i)\r\n" );
document.write( "a + b – c = 3 --------- eq (ii)\r\n" );
document.write( "2c = 7 ------- Subtracting eq (ii) from eq (i)\r\n" );
document.write( "c = \"7%2F2\", or 3.5\r\n" );
document.write( "\r\n" );
document.write( "a + b + 3.5 = 10 -- Substituting 3.5 for c in eq (i)\r\n" );
document.write( "a + b = 6.5 ------- eq (iii)\r\n" );
document.write( "OR\r\n" );
document.write( "a + b - 3.5 = 3 --- Substituting 3.5 for c in eq (ii)\r\n" );
document.write( "a + b = 6.5 ------- eq (iv)\r\n" );
document.write( "\r\n" );
document.write( "As seen a + b = 6.5, so 
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