document.write( "Question 1062333: An airplane travels 1000 miles on a bearing of 210°. Then, it changes to a bearing 270° and travels 500 miles. How far is the airplane from the starting point?\r
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document.write( "https://cds.flipswitch.com/tools/asset/media/573164\r
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document.write( "What is the measure of ∠ABC? \r
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document.write( "m∠ABC= __________°\r
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document.write( "Which of the following laws would help you to find the length of AC¯?\r
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document.write( "Law of Cosines
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document.write( "Law of Sines\r
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document.write( "How far is the airplane from the starting point? \r
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document.write( "AC≈ __________ miles\r
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document.write( "Enter your answer as the number rounded to the nearest hundredth that correctly fills in the blank in the previous sentence.\r
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Algebra.Com's Answer #677210 by Boreal(15235) You can put this solution on YOUR website! Angle ABC is 120 degrees. Parallel lines perpendicular to the new course are cut by a transversal that was the first leg of the trip. That course is angled 30 degrees to the 180-360 degree line. The other alternate interior angle is therefore 30 degrees, and that is added to the 90 degrees from due north that the plane is now flying. \n" ); document.write( "Law of Cosines: \n" ); document.write( "c^2=a^2+b^2-2ab cos C \n" ); document.write( "c^2=1000^2+500^2-2*1000*500*cos 120 \n" ); document.write( "=1750000. \n" ); document.write( "c=1322.88 miles \n" ); document.write( " |