document.write( "Question 93075: A sprinter who averaged 30ft/sec completed a race one second before another sprinter who averaged 28 ft/sec. what was the distance of the race? \n" ); document.write( "
Algebra.Com's Answer #67717 by stanbon(75887)\"\" \"About 
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A sprinter who averaged 30ft/sec completed a race one second before another sprinter who averaged 28 ft/sec. what was the distance of the race?
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\n" ); document.write( "1st sprinter DATA:
\n" ); document.write( "Rate = 30 ft/sec ; Time = x seconds ; distance = rt = 30x ft.
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\n" ); document.write( "2nd sprinter DATA:
\n" ); document.write( "Rate = 28 ft/sec ; Time = x+1 seconds ; diatance = rt = 28(x+1) = 28x + 28 ft.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "distance = distance
\n" ); document.write( "30x = 28x + 28
\n" ); document.write( "2x = 28
\n" ); document.write( " x = 14 seconds
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\n" ); document.write( "Distance of the race = 30x = 30*14 = 420 ft.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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