document.write( "Question 93075: A sprinter who averaged 30ft/sec completed a race one second before another sprinter who averaged 28 ft/sec. what was the distance of the race? \n" ); document.write( "
Algebra.Com's Answer #67717 by stanbon(75887) ![]() You can put this solution on YOUR website! A sprinter who averaged 30ft/sec completed a race one second before another sprinter who averaged 28 ft/sec. what was the distance of the race? \n" ); document.write( "--------------- \n" ); document.write( "1st sprinter DATA: \n" ); document.write( "Rate = 30 ft/sec ; Time = x seconds ; distance = rt = 30x ft. \n" ); document.write( "--------------- \n" ); document.write( "2nd sprinter DATA: \n" ); document.write( "Rate = 28 ft/sec ; Time = x+1 seconds ; diatance = rt = 28(x+1) = 28x + 28 ft. \n" ); document.write( "----------------- \n" ); document.write( "EQUATION: \n" ); document.write( "distance = distance \n" ); document.write( "30x = 28x + 28 \n" ); document.write( "2x = 28 \n" ); document.write( " x = 14 seconds \n" ); document.write( "--------------- \n" ); document.write( "Distance of the race = 30x = 30*14 = 420 ft. \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |