document.write( "Question 1062292: a car leaves an intersection traveling at an average speed of 56 miles per hour. ten minutes later a second car leave the same intersection and travels on a road making an angle of 112 with the first car, at an average speed of 54 miles per house. assuming the roads are straight, how far apart are the cars 30 minutes after the first car has left? \n" ); document.write( "
Algebra.Com's Answer #677151 by josgarithmetic(39617)\"\" \"About 
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document.write( "                      SPEED          TIME       DISTANCE\r\n" );
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document.write( "FIRSTCAR               56           \"t\"          \"56t%29\"\r\n" );
document.write( "SECCAR                 54            \"t%2B1%2F6\"     \"54%2A%28t%2B1%2F6%29\"\r\n" );
document.write( "DISTANCE 112 Degrees                            Law Of Cosines\r\n" );
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\n" ); document.write( "\n" ); document.write( "Careful with Law of Cosines. The angle between the cars is 112 degrees and the cosine must be the negative value. \"-cos%28112-90%29=-cos%2822%29=-0.92718=cos%28112%29\"\r
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\n" ); document.write( "\n" ); document.write( "Distance d between the cars any time t is
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\n" ); document.write( "That is the formula. Simplify any way you like, and then substitute \"t=1%2F2\" to evaluate d.
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