document.write( "Question 1062269: Sean is 26 years old. He is 8 years older than John. How many years ago was Sean's age three time John's age? \n" ); document.write( "
Algebra.Com's Answer #677125 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
s=26
\n" ); document.write( "s=j+8
\n" ); document.write( "-
\n" ); document.write( "\"26=j%2B8\"
\n" ); document.write( "\"j=26-8\"
\n" ); document.write( "\"j=18\"
\n" ); document.write( "Current ages are \"system%28s=26%2Cj=18%29\".\r
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\n" ); document.write( "\n" ); document.write( "x, how many years ago\r
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\n" ); document.write( "\n" ); document.write( "\"s-x=3%28j-x%29\"
\n" ); document.write( "\"s-x=3j-3x\"
\n" ); document.write( "\"s=3j-2x\"
\n" ); document.write( "\"s-3j=-2x\"
\n" ); document.write( "\"highlight_green%28x=%283j-s%29%2F2%29\"
\n" ); document.write( "Current ages s and j are already solved or known now, so substitute.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%283%2A18-26%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=3%2A9-13\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=27-13\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28x=14%29\"
\n" ); document.write( "Fourteen years ago
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