document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1062230>Question 1062230</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ship is sailing in the ocean when a passenger notices a submarine located 2.3 meters below the surface of the water. The angle of depression from the edge of the ship at the surface of the water to the submarine is 25.6°. What is the horizontal distance from the ship to the submarine, rounded to the nearest tenth of a meter? \r<BR>\n" );
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document.write( "4.8 m<BR>\n" );
document.write( "2.6 m<BR>\n" );
document.write( "5.3 m<BR>\n" );
document.write( "1.1 m<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #677099 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=677099\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "Consider your problem as a right angled triangle.<BR>\n" );
document.write( "Depth of submarine = opposite side = 2.3 metres<BR>\n" );
document.write( "Angle of Depression = 25.6 degrees.<BR>\n" );
document.write( "Horizontal distance of ship = Adjacent side.<BR>\n" );
document.write( "Tan = Opposite/Adjacent<BR>\n" );
document.write( "Tan(25.6) = 2.3/Adjacent<BR>\n" );
document.write( "Cross multiply<BR>\n" );
document.write( "Adjacent x Tan(25.6) = 2.3<BR>\n" );
document.write( "Adjacent = 2.3/Tan(25.6)<BR>\n" );
document.write( "Adjacent = 4.8 metres.<BR>\n" );
document.write( "Horizontal distance = 4.8 metres.<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
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