document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1062246>Question 1062246</A>: <I><SPAN STYLE=\"word-break: break-all;\"> when 100 is added to a number,the result is 50 more than 3 times the number.find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #677088 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=677088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number be x:<BR>\n" );
document.write( "x+100 = 3x+50 let's flip the equation<BR>\n" );
document.write( "3x+50 = x+100 now subtract 1x and 50 on both sides<BR>\n" );
document.write( "2x = 50<BR>\n" );
document.write( "x = 25<BR>\n" );
document.write( "-.-.-.-.-.-.-.-.-.-.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "100+25 = 3(25)+50 Complete the operations to find that it is correct.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "john </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );