document.write( "Question 93017: If the average (arithmetic mean) of x and y is k, which of the following is the average of x, y, and z?\r
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document.write( "(A) 2k + z/3
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document.write( "(B) 2k +z/2
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document.write( "(C) k+z/3
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document.write( "(D) k+z/2
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document.write( "(E) 2(k+z)/3 \n" );
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Algebra.Com's Answer #67703 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! None of the given answers are correct. \n" ); document.write( ". \n" ); document.write( "Here's how you do the problem. \n" ); document.write( ". \n" ); document.write( "You are told that the average of x and y is equal to k. But how do you find the average \n" ); document.write( "of x and y? You add them together and divide by 2. So the average of x and y is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and setting that equal to k you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Get rid of the denominator by multiplying both sides of this equation by 2: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Cancel the two in the numerator and the two in the denominator on the left side: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and we end up with: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Remember this result. \n" ); document.write( ". \n" ); document.write( "Now let's find the average (call it A) of x, y, and z. To average these three you add them \n" ); document.write( "together and divide by 3. In equation form this becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "but recall that \n" ); document.write( "for A. When we make that substitution, the answer for A is given by the equation: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The right side of this equation is the form of the answer. Notice that A equals a quantity \n" ); document.write( "that is divided by 3. So in your answer list you can eliminate answers B and D because \n" ); document.write( "they are divided by 2, not 3. \n" ); document.write( ". \n" ); document.write( "By the rules of algebraic combination for single line expressions, the other answers are: \n" ); document.write( ". \n" ); document.write( "(A) \n" ); document.write( ". \n" ); document.write( "(C) \n" ); document.write( ". \n" ); document.write( "(E) \n" ); document.write( ". \n" ); document.write( "I suppose that (A) is supposed to be the correct answer, but it sure isn't written \n" ); document.write( "that way. The way it is written is: \n" ); document.write( ". \n" ); document.write( "(A) 2k + z/3 \n" ); document.write( ". \n" ); document.write( "This actually translates to \n" ); document.write( "you do the division first and then you do the addition. \n" ); document.write( ". \n" ); document.write( "Instead, it should have been written: \n" ); document.write( ". \n" ); document.write( "(A) (2k + x)/3 \n" ); document.write( ". \n" ); document.write( "In this form you divide everything inside the parentheses by 3 which translates to \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Hope this clarifies the problem for you and helps you to see your way through it. \n" ); document.write( " |