document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1839>Question 1839</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mother is 6 times older than her daughter is today, and in 20 years from today, the mother will be twice the child's age.  What is the daughter's age today?  And, what is the equation for solving this problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #677 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Definitions:\r<BR>\n" );
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document.write( "Let m = mothers age today<BR>\n" );
document.write( "Let d = daughters age today\r<BR>\n" );
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document.write( "So, we know m = 6d  --1<BR>\n" );
document.write( "and  (m+20) = 2(d+20)  --2\r<BR>\n" );
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document.write( "sub 1 into 2, giving (6d+20) = (2d+40)<BR>\n" );
document.write( "then re-arragne to give 4d = 20. therefore d=5 and hence m=30\r<BR>\n" );
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document.write( "cheers<BR>\n" );
document.write( "Jon </SPAN>\n" );
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