document.write( "Question 167728: Verify this identity :\r
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document.write( "(tan^2(x)-1)/(1+tan^2(x)) = 1-2cos^2(x)\r
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document.write( "I've started a couple different options but none are working out for me. Here is what I have so far :\r
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document.write( "A)
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document.write( "multiply top by (1 + tan^2(x)) to get :
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document.write( "tan^4 (x) -1 or (tan^2(x)+1)(tan^2x-1)
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document.write( "then i'm stuck!\r
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document.write( "B) (tanx +1)(tanx-1)/1 + tan^2(x) =
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document.write( "(sinx/cosx + 1)(sinx/cosx - 1) / 1/cosx
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document.write( "then again I'm stuck!\r
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document.write( "I'm not sure if I should be working on the right side of the equation instead! Grrrrr....I could get a little help from the tutors in the Math Lab on campus but we've been instructed not to seek them out for this problem (and another I am stuck on!). Any tips would be helpful and thank you in advance for your time!!\r
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document.write( "Desperately seeking solution, Rebecca
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Algebra.Com's Answer #676989 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Verify this identity : \n" ); document.write( "(tan^2(x)-1)/(1+tan^2(x)) = 1-2cos^2(x) \n" ); document.write( "Verify this identity : \n" ); document.write( "(tan^2(x)-1)/sec^2 = 1-2cos^2(x) \n" ); document.write( "Mulitiply by cos^2 \n" ); document.write( "(sin^2 - cos^2)/1 = 1 - 2cos^2 \n" ); document.write( "Add cos^2 \n" ); document.write( "sin^2 = 1 - cos^2 \n" ); document.write( "QED \n" ); document.write( " \n" ); document.write( " |