document.write( "Question 1062128: > a guy has 120grams worth of candy. If the ten gram sweets are half the number of five gram sweets how many sweets does he have in total?\r
\n" ); document.write( "\n" ); document.write( ">solve the simultaneous equation
\n" ); document.write( "I) (1/x)+(1/y)=7/10
\n" ); document.write( "II) (3/x)-(5/y)=1/2 \n" ); document.write( "

Algebra.Com's Answer #676973 by MathTherapy(10552) $\"\"$ $\"About$

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> a guy has 120grams worth of candy. If the ten gram sweets are half the number of five gram sweets how many sweets does he have in total?\r
\n" ); document.write( "\n" ); document.write( ">solve the simultaneous equation
\n" ); document.write( "I) (1/x)+(1/y)=7/10
\n" ); document.write( "II) (3/x)-(5/y)=1/2
\n" ); document.write( "

Let number of 10-gram sweets be T
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document.write( "Then number of 5-gram sweets = 2T
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document.write( "We then get: 10T + 5(2T) = 120
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document.write( "10T + 10T = 120
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document.write( "20T = 120
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document.write( "T, or number of 10-gram sweets = 
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document.write( "From this, you should be able to determine how many 5-gram sweets there are, and the total number. You shouldn't need my help for that. \n" );
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