document.write( "Question 1061060: Find three consecutive natural numbers such that the square of the smallest number is 65 less than the product of the remaining two numbers. \n" ); document.write( "

Algebra.Com's Answer #676951 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let the three numbers be N-1, N, and N+1.
\n" ); document.write( " $\"%28N-1%29%5E2=N%28N%2B1%29-65\"$
\n" ); document.write( " $\"N%5E2-2N%2B1=N%5E2%2BN-65\"$
\n" ); document.write( " $\"-3N=-66\"$
\n" ); document.write( " $\"N=22\"$
\n" ); document.write( "So the numbers are 21,22, and 23.
\n" ); document.write( "Verifying,
\n" ); document.write( " $\"21%5E2=22%2A23-65\"$
\n" ); document.write( " $\"441=506-65\"$
\n" ); document.write( " $\"441=441\"$
\n" ); document.write( "True, good solution.
\n" ); document.write( " \n" ); document.write( "

\n" );