document.write( "Question 1062126: a jury consists of five men and seven women. Three are selected at random for an interview. Find the probability that all three are men. \n" ); document.write( "
Algebra.Com's Answer #676928 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "There are 5+7 = 12 total people. \n" ); document.write( "- \n" ); document.write( "The probability that the first person picked is a man is 5/12. \n" ); document.write( "Pr{2nd is also a man} = 4/11 \n" ); document.write( "Pr(3rd is also a man) = 3/10 \n" ); document.write( "- \n" ); document.write( "Pr{all 3 are men} = (5/12)(4/11)(3/10) = 60/1320 = 1/22 = 0.04545.... \n" ); document.write( "- \n" ); document.write( " \n" ); document.write( " |