document.write( "Question 1062011: At the time she was hired as a server at the Grumney Family Restaurant, Beth Brigden was told, “You can average $80 a day in tips.” Assume the population of daily tips is normally distributed with a standard deviation of $2.81. Over the first 42 days she was employed at the restaurant, the mean daily amount of her tips was $82.74. At the 0.10 significance level, can Ms. Brigden conclude that her daily tips average more than $80?
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document.write( "a. State the null hypothesis and the alternate hypothesis.
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document.write( " H0: μ ≥ 80 ; H1: μ < 80
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document.write( " H0: μ = 80 ; H1: μ ≠ 80
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document.write( " H0: μ >80 ; H1: μ = 80
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document.write( " H0: μ ≤ 80 ; H1: μ > 80
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document.write( "b. State the decision rule.
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document.write( " Reject H1 if z > 1.28
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document.write( " Reject H0 if z < 1.28
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document.write( " Reject H0 if z > 1.28
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document.write( " Reject H1 if z < 1.28
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document.write( "c. Compute the value of the test statistic. (Round your answer to 2 decimal places.)
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document.write( " Value of the test statistic
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document.write( "d. What is your decision regarding H0?
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document.write( " Do not reject H0
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document.write( " Reject H0
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document.write( "e. What is the p-value? (Round your answer to 4 decimal places.)
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document.write( " p-value
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Algebra.Com's Answer #676863 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! It's mu=80 vs. mu NE 80. \"You can average $80/day in tips.\" That means it could be on either side or a two way test.\r \n" ); document.write( "\n" ); document.write( "For the next part, reject Ho if |z|>1.28. That isn't one of the choices, so I would say reject Ho if z>1.28. \n" ); document.write( "The test statistic is z=(82.74-80)/2.81/sqrt (42). \n" ); document.write( "That is 2.74*sqrt(42)/2.81=6.32. Reject Ho. \n" ); document.write( "This is highly significant at < 0.0001 level \n" ); document.write( " |