document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1061991>Question 1061991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> logarithmic expression for x\r<BR>\n" );
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document.write( "log12 x/30=2\r<BR>\n" );
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document.write( "Says you can also convert to an exponential equation but isn't required. \r<BR>\n" );
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document.write( "Which way is easier and how would you do both? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #676807 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=676807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log12 (x/30) = 2<BR>\n" );
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document.write( "Use this to convert to base e:  log_b( n ) = ln( n ) / ln(b)<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+ln%28x%2F30%29%2Fln%2812%29+=+2+ ALIGN=MIDDLE  ALT=\"+ln%28x%2F30%29%2Fln%2812%29+=+2+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=++ln%28x%2F30%29+=+2%2Aln%2812%29+ ALIGN=MIDDLE  ALT=\"++ln%28x%2F30%29+=+2%2Aln%2812%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=++e%5Eln%28x%2F30%29+=+e%5E%282%2Aln%2812%29%29+ ALIGN=MIDDLE  ALT=\"++e%5Eln%28x%2F30%29+=+e%5E%282%2Aln%2812%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >   (convert to exponential, e^(both sides))<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+++x%2F30+=+144+ ALIGN=MIDDLE  ALT=\"+++x%2F30+=+144+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=++x+=+30%2A144+ ALIGN=MIDDLE  ALT=\"++x+=+30%2A144+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=++x+=+4320++ ALIGN=MIDDLE  ALT=\"++x+=+4320++\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Ans:  x=4320<BR>\n" );
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document.write( "Check:  log12(4320 / 30) = log12(144) = 2  (ok)\r<BR>\n" );
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document.write( "Sorry, forgot to address the question about not using exponential.  The only ways (that I can see) without using exponentiation would be to use trial-and-error  or to reason it out.  For example, one can ask this question  log12(n) = 2, what is n?   Well, n has to be 144 because 12^2 = 144.  With that knowledge, one can say what x is, given x/30 = 144?   x = 30*144 = 4320.   However, this approach probably gets more challenging if the exponent is not an integer :-)\r<BR>\n" );
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