document.write( "Question 1062040: What is the answer oh this given 2x+y=10 2x+3y=6? \n" ); document.write( "
Algebra.Com's Answer #676804 by math_helper(2461)\"\" \"About 
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You have two equations and two unknowns. As long as they're linearly independent (i.e. not exact multiples of one another) there should be a solution:
\n" ); document.write( "\"+2x+%2B+y+=+10+\" (1)
\n" ); document.write( "\"+2x+%2B+3y+=+6+\" (2)\r
\n" ); document.write( "\n" ); document.write( "Subtract (2) from (1), to get:
\n" ); document.write( "\"+0x+-+2y+=+4+\"
\n" ); document.write( "\"++++++++++y+=+4%2F%28-2%29+=+-2+\"
\n" ); document.write( "\"++y=-2+\" — using (1) —> \"+2x+-+2+=+10+\" or \"+x+=+6+\"\r
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\n" ); document.write( "\n" ); document.write( "Ans: x=6, y=-2
\n" ); document.write( "—
\n" ); document.write( "Check (using (2), we already used (1) to find x):
\n" ); document.write( " 2(6) + 3(-2) = 12 - 6 = 6 (ok)
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