document.write( "Question 1062030: Let P be a projection, so \"P%5E2+=+P\". If \"c%3C%3E1\", compute \"%28I-cP%29%5E%28-1%29\". \n" ); document.write( "
Algebra.Com's Answer #676786 by ikleyn(52817)\"\" \"About 
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\n" ); document.write( "Let P be a projection, so \"P%5E2+=+P\". If \"c%3C%3E1\", compute \"%28I-cP%29%5E%28-1%29\".
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\n" ); document.write( "\n" ); document.write( "I can do it for  \"abs%28c%29\" < 1.  Again,  let us assume that  |c| < 1.\r
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document.write( "Then  \"%28I-cP%29%5E%28-1%29\" = \"1+%2B+cP+%2B+%28cP%29%5E2+%2B+%28cP%29%5E3+%2B+ellipsis\" = (since \"P%5E2+=+P+\") = \"1+%2B+cP+%2B+c%5E2%2AP+%2B+c%5E3%2AP+%2B+ellipsis\" = \r\n" );
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document.write( "      ( apply the formula for the sum of an infinite geometric progression ) \r\n" );
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document.write( "      = \"1+%2B+c%2A%281+%2B+c+%2B+c%5E2+%2B+c%5E3+%2B+ellipsis%29%2AP%29\" = \"1+%2B+c%2A%281%2F%281-c%29%29%2AP\" = \r\n" );
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document.write( "      = \"1+%2B+%28c%2F%281-c%29%29%2AP\" = \"%28%281-c+%2B+c%29%2F%281-c%29%29%2AP\" = \"%281%2F%281-c%29%29%2AP\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer. \"%28I-cP%29%5E%28-1%29\" = \"%281%2F%281-c%29%29%2AP\".\r
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\n" ); document.write( "\n" ); document.write( "You may check it by making direct calculations that   \"%28I+-+cP%29\" * \"%281%2F%281-c%29%29%2AP\" = I   under the condition   \"P%5E2\" = \"P\".\r
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\n" ); document.write( "\n" ); document.write( "And after checking it directly  (as I said)  you may to extend the formula for  |c| > 1.  It is valid for  |c| > 1,  too.\r
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