document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1062023>Question 1062023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a certain candy store, 3 pounds of candy and 2 pounds of mints cost $10.80, and 1 pound of candy and 3 pounds of mints cost $5.35. What is the cost per pound of the mints?\r<BR>\n" );
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document.write( "A.)mints are 65¢ per lb<BR>\n" );
document.write( "B.)mints are 75¢ per lb<BR>\n" );
document.write( "C.)mints are 85¢ per lb </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #676777 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=676777\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3c+2m = 10.80 (1)<BR>\n" );
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document.write( "1c+3m = 5.35 multiply both sides times 3:<BR>\n" );
document.write( "3c+9m =16.05 (2)<BR>\n" );
document.write( "Now subtract (2) from (1):<BR>\n" );
document.write( "3c+2m = 10.80 <BR>\n" );
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document.write( "3c+9m =16.05 <BR>\n" );
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document.write( "0c+(-7m) = -5.25<BR>\n" );
document.write( "-7m = -5.25 divide both sides by 7 and remember that -/- = +<BR>\n" );
document.write( "m = 0.75 This is the cost per pound of the mints.<BR>\n" );
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document.write( "John </SPAN>\n" );
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