document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1061977>Question 1061977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Y=2/3x-3 in standard form? How do I solve this?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #676742 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=676742\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "y = (2/3)x - 3<BR>\n" );
document.write( "3y = 2x - 9     ( multiplied both sides by 3)<BR>\n" );
document.write( "-2x + 3y  = -9    (subtracted 2x from both sides)<BR>\n" );
document.write( "-2x + 3y + 9 = 0   (added 9 to both sides)<BR>\n" );
document.write( "-2x + 3y + 9 = 0  is standard form of a straight line<BR>\n" );
document.write( "—<BR>\n" );
document.write( "if you prefer the coefficient of x to be positive, you can multiply the above by -1:<BR>\n" );
document.write( "2x - 3y - 9 = 0\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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