document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1061954>Question 1061954</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number of bacteria in a certain population increases according to a continuous exponential growth model, with a growth rate parameter of <BR>\n" );
document.write( "9.3%<BR>\n" );
document.write( " per hour. How many hours does it take for the size of the sample to double? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #676719 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=676719\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let p be the population size, then<BR>\n" );
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document.write( "2p = p * e^(0.093 * t)<BR>\n" );
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document.write( "2 = e^(0.093 * t)<BR>\n" );
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document.write( "0.093 * t = ln(2)<BR>\n" );
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document.write( "Note use definition of logarithm<BR>\n" );
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document.write( "t = ln(2) / 0.093 = 7.4532<BR>\n" );
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document.write( "Population doubles in approximately 7.45 hours<BR>\n" );
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