document.write( "Question 1061893: If one were to cut five circles, each 2 cm in diameter, from a rectangular piece of paper 6 cm long, at
\n" ); document.write( "least how many cm’s wide would the piece of paper have to be?
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Algebra.Com's Answer #676710 by KMST(5328)\"\" \"About 
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Here are 5 circles (with their centers) packed as tightly as I can pack them:
\n" ); document.write( "If each circle has \"diameter=2cm\" <---> \"radius=1cm\" ,
\n" ); document.write( "the green rectangles have \"length=6cm\" .
\n" ); document.write( "For the rectangle to the left of all centers,
\n" ); document.write( "and for the one to the right of all centers,
\n" ); document.write( "\"width=1cm\" .
\n" ); document.write( "As for the (middle) green rectangle going through all the circle centers,
\n" ); document.write( "looking at the red equilateral and right triangles
\n" ); document.write( "we can calculate its width.
\n" ); document.write( "For the right triangles,
\n" ); document.write( "\"hypotenuse=2cm\" and \"short\"\"leg=1cm\" .\r
\n" ); document.write( "\n" ); document.write( "So, according to the Pythagorean theorem,
\n" ); document.write( "the long leg measures
\n" ); document.write( "\"sqrt%28%282cm%29%5E2%2B%281cm%29%5E2%29=sqrt%283%29\"\"cm\" .
\n" ); document.write( "So the overall width encased in green (in cm) is
\n" ); document.write( "\"1%2B1%2Bsqrt%283%29=highlight%282%2Bsqrt%283%29=about3.732%29\" .
\n" ); document.write( "So I would say the width of the piece of paper has to be at least
\n" ); document.write( "\"highlight%283.74cm%29\" or more realistically \"highlight%283.8cm%29\" .
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