document.write( "Question 92979: The sum of two numbers is 112. the second is 7 more than 4 times the first. What are the two numbers? \n" ); document.write( "
Algebra.Com's Answer #67671 by jim_thompson5910(35256)\"\" \"About 
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\"x%2By=112\" \"The sum of two numbers is 112.\"\r
\n" ); document.write( "\n" ); document.write( "\"y=4x%2B7\" \"The second is 7 more than 4 times the first.\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B%284x%2B7%29=112\" Plug in \"y=4x%2B7\"\r
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\n" ); document.write( "\n" ); document.write( "\"5x%2B7=112\" Combine the variable terms x and 4x on the left side to get 5x\r
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\n" ); document.write( "\n" ); document.write( "\"5x=112-7\" Subtract 7 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"5+x=105\" Combine like terms -7 and 112 on the right side to get 105\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28105%29%2F%285%29\" Now divide both sides by 5 to isolate and solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x=+21\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So one answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=+21\"\r
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\n" ); document.write( "\n" ); document.write( "Now plug in x=21 into \"y=4x%2B7\" to find y\r
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\n" ); document.write( "\n" ); document.write( "\"y=4%2821%29%2B7\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=84%2B7\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=91\"\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers are 21 and 91\r
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\n" ); document.write( "\n" ); document.write( "\"21%2B91=112\" plug in x=21, y=91\r
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\n" ); document.write( "\n" ); document.write( "\"112=112\" works
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