document.write( "Question 92970: 2(4^x+1) = 1\r
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Algebra.Com's Answer #67660 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2%284%5E%28x%2B1%29%29+=+1\"\r
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\n" ); document.write( "\n" ); document.write( "\"4%5E%28x%2B1%29+=+1%2F2\" Divide both sides by 2\r
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\n" ); document.write( "\n" ); document.write( "\"%28%281%2F2%29%5E%28-2%29%29%5E%28x%2B1%29+=+1%2F2\" Rewrite 4 as \"%281%2F2%29%5E%28-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F2%29%5E%28-2%28x%2B1%29%29+=+1%2F2\" Multiply the exponents\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F2%29%5E%28-2x-2%29+=+1%2F2\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F2%29%5E%28-2x-2%29+=+%281%2F2%29%5E1\" Rewrite \"1%2F2\" as \"%281%2F2%29%5E1\"\r
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\n" ); document.write( "\n" ); document.write( "Now that we have the same base, we can set the exponents equal to each other\r
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\n" ); document.write( "\n" ); document.write( "\"-2x=1%2B2\" Add 2 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-2+x=3\" Combine like terms 2 and 1 on the right side to get 3\r
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\n" ); document.write( "\n" ); document.write( "\"x=%283%29%2F%28-2%29\" Now divide both sides by -2 to isolate and solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x=+-3+%2F+2\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So our answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=+-3+%2F+2\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%284%5E%28x%2B1%29%29+=+1\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"2%284%5E%28%28-3%2F2%29%2B1%29%29+=+1\" Plug in \"x=-3+%2F+2\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%284%5E%28-1%2F2%29%29+=+1\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"2%28sqrt%284%5E-1%29%29+=+1\" Rewrite \"4%5E%28-1%2F2%29\" as \"sqrt%284%5E-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%28sqrt%281%2F4%29%29+=+1\" Evaluate \"4%5E-1\" to get \"1%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%281%2F2%29+=+1\" Take the square root of \"1%2F4\" to get \"1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"1+=+1\" Multiply. Since the two equations are equal, this verifies our answer.\r
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