document.write( "Question 1061628: 10. Suppose the random variable X has a normal distribution with mean 9.0 and variance 49. The probability that X takes on a value of at least 18 is approximately equal to\r
\n" ); document.write( "\n" ); document.write( "A. .0985\r
\n" ); document.write( "\n" ); document.write( "B. .4015\r
\n" ); document.write( "\n" ); document.write( "C. .9015\r
\n" ); document.write( "\n" ); document.write( "D. Correct approx. answer not given
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Algebra.Com's Answer #676576 by Fombitz(32388)\"\" \"About 
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Variance of 49 leads to \"sigma=sqrt%2849%29=7\"
\n" ); document.write( "So then the z score of X=18 is,
\n" ); document.write( "\"z=%2818-9%29%2F7=9%2F7\"
\n" ); document.write( "The probability for this z score is,
\n" ); document.write( "\"P%289%2F7%29=0.900729\"
\n" ); document.write( "So this is the probability that the score is 18 or less.
\n" ); document.write( "To find the answer, find the complement.
\n" ); document.write( "\"P=1-0.900729\"
\n" ); document.write( "\"P=0.099271\"
\n" ); document.write( "D. Correct approx. answer not given
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