document.write( "Question 1061817: Find three consecutive odd integers such that 6 times the sum of the first and second is 16 more than 8 times the third. \n" ); document.write( "
Algebra.Com's Answer #676568 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x, x+2, x+4 \n" ); document.write( "6(2x+2)-16=8(x+4) \n" ); document.write( "12x+12-16=8x+32 \n" ); document.write( "12x-4=8x+32 \n" ); document.write( "4x=36 \n" ); document.write( "x=9 \n" ); document.write( "9,11,13 \n" ); document.write( "6 times the sum of 9 and 11 is 6(20)=120, and that is 16 more than 8(13)=104 \n" ); document.write( " |