document.write( "Question 1061817: Find three consecutive odd integers such that 6 times the sum of the first and second is 16 more than 8 times the third. \n" ); document.write( "
Algebra.Com's Answer #676568 by Boreal(15235)\"\" \"About 
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x, x+2, x+4
\n" ); document.write( "6(2x+2)-16=8(x+4)
\n" ); document.write( "12x+12-16=8x+32
\n" ); document.write( "12x-4=8x+32
\n" ); document.write( "4x=36
\n" ); document.write( "x=9
\n" ); document.write( "9,11,13
\n" ); document.write( "6 times the sum of 9 and 11 is 6(20)=120, and that is 16 more than 8(13)=104
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