document.write( "Question 1061742: It took 3 hours for a plane, flying against the wind, to travel 900 miles from Alabama to Minnesota. The \"ground speed\" of the plane is 300 miles per hour. On the return trip, the flight took only 2 hours with a ground speed of 450 miles per hour. During both flights the speed and the direction of the wind were the same. Find the speed of the plane in still air and the speed of the wind. \n" ); document.write( "
Algebra.Com's Answer #676503 by stanbon(75887)\"\" \"About 
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It took 3 hours for a plane, flying against the wind, to travel 900 miles from Alabama to Minnesota. The \"ground speed\" of the plane is 300 miles per hour. On the return trip, the flight took only 2 hours with a ground speed of 450 miles per hour. During both flights the speed and the direction of the wind were the same. Find the speed of the plane in still air and the speed of the wind.
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\n" ); document.write( "With wind:: p + c = 450
\n" ); document.write( "Against::: p - c = 300
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\n" ); document.write( "Add and solve for p::
\n" ); document.write( "2p = 750
\n" ); document.write( "plane = 375 mph (plane rate in still air)
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\n" ); document.write( "Solve for \"c\":
\n" ); document.write( "p + c = 450
\n" ); document.write( "c = 450-375 = 75 mph (rate of the wind)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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