document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1061724>Question 1061724</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can someone help me simplify 5&#8730;-32/5&#8730;243 please not sure how to.\r<BR>\n" );
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document.write( "thank you in advance really grateful 	 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #676481 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=676481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am assuming the problem is 5*sqrt(-32)/5* sqrt (243). Cancel the 5 right away<BR>\n" );
document.write( "The numerator is i sqrt(32), but sqrt (32)=sqrt (16)*sqrt (2)=4 sqrt (2)<BR>\n" );
document.write( "4i sqrt (2)<BR>\n" );
document.write( "divided by  sqrt (243)<BR>\n" );
document.write( "243=3^5<BR>\n" );
document.write( "Therefore sqrt (3^5) is sqrt (3*3*3*3*3)=3*3*sqrt (3)=9 sqrt (3)<BR>\n" );
document.write( "The answer is <BR>\n" );
document.write( "4i sqrt (2)/9 sqrt (3)<BR>\n" );
document.write( "rationalize the denominator by multiplying top and bottom by sqrt (3)<BR>\n" );
document.write( "4i sqrt(6)/9*3<BR>\n" );
document.write( "4i sqrt (6)/27 </SPAN>\n" );
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