document.write( "Question 1061728: Please help me with this problem:\r
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document.write( "a pool and a basketball court are both rectangular in shape. the pool's length is twice it's width. the basketball court has the same length as the pool, but its length is 3/4 the length of the pool. 10 less than the perimeter of the pool is equal to the perimeter of the basketball court. find the dimensions of both courts \n" );
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Algebra.Com's Answer #676480 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! pool's width is x \n" ); document.write( "length is 2x \n" ); document.write( "basketball court can't have the same length as the pool , but its length is 3/4 the length of the pool. I will assume the WIDTH is the same and the length is 3/4 that of the pool. \n" ); document.write( "That makes the basketball court x by 1.5x (3/4*2x) \n" ); document.write( "The perimeter of the pool is 6x, twice the half perimeter of L+W \n" ); document.write( "The perimeter of the basketball court is 6x-10=(x+1.5x)*2 \n" ); document.write( "Therefore, 6x-10=5x \n" ); document.write( "x=10 units \n" ); document.write( "2x=20 units \n" ); document.write( "The pool is 10 *20 with perimeter 60. \n" ); document.write( "The basketball court is 10*15 with perimeter 50, 10 fewer than 60. \n" ); document.write( " \n" ); document.write( " |