document.write( "Question 1061720: How do I solve for a in the problem 4a+2=3b-5 ? \n" ); document.write( "
Algebra.Com's Answer #676475 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "That 4 in that last step in the solution above\r\n" ); document.write( "should be divided, not multiplied.\r\n" ); document.write( "\r\n" ); document.write( "Here's the solution in more detail: \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "4a+2 = 3b-5\r\n" ); document.write( "\r\n" ); document.write( "Get rid of the +2 on the left by adding -2 to both sides:\r\n" ); document.write( "\r\n" ); document.write( "4a+2 = 3b-5\r\n" ); document.write( " -2 -2\r\n" ); document.write( "-----------\r\n" ); document.write( "4a+0 = 3b-7\r\n" ); document.write( "\r\n" ); document.write( "Ignore the 0:\r\n" ); document.write( "\r\n" ); document.write( "4a = 3b-7\r\n" ); document.write( "\r\n" ); document.write( "Get rid of the multiplied 4 by dividing both sides by 4:\r\n" ); document.write( "\r\n" ); document.write( " 4a 3b-7\r\n" ); document.write( "覧覧 = 覧覧\r\n" ); document.write( " 4 4\r\n" ); document.write( "\r\n" ); document.write( "Cancel the 4's on the left\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |