document.write( "Question 1061689: If we assume that air resistance is proportional to the square of the velocity, then the time t in seconds
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\n" ); document.write( "t=9/24ln 24+v/24-v, 0 ≤ v < 24
\n" ); document.write( "determine the velocity, to the nearest hundredth foot per second of the object after 1.3 seconds
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Algebra.Com's Answer #676463 by ikleyn(52832)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "If we assume that air resistance is proportional to the square of the velocity, then the time t in seconds
\n" ); document.write( "required for an object to reach a velocity v in feet per second is given by:
\n" ); document.write( "t=9/24ln 24+v/24-v, 0 < v < 24
\n" ); document.write( "determine the velocity, to the nearest hundredth foot per second of the object after 1.3 seconds
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document.write( "If your formula is\r\n" );
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document.write( "t = \"%289%2F24%29%2Aln%28%2824%2Bv%29%2F%2824-v%29%29\" \r\n" );
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document.write( "then they want you to solve this equation for \"v\":\r\n" );
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document.write( "1.3 = \"%289%2F24%29%2Aln%28%2824%2Bv%29%2F%2824-v%29%29\".\r\n" );
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document.write( "It is equivalent to\r\n" );
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document.write( "\"1.3%2A%2824%2F9%29\" = \"ln%28%2824%2Bv%29%2F%2824-v%29%29\"    or\r\n" );
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document.write( "\"ln%28%2824%2Bv%29%2F%2824-v%29%29\" = 3.4666,\r\n" );
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document.write( "\"%2824%2Bv%29%2F%2824-v%29\" = \"e%5E3.4666%29\",\r\n" );
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document.write( "\"%2824%2Bv%29%2F%2824-v%29\" = \"2.71828%5E3.4666\",\r\n" );
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document.write( "\"%2824%2Bv%29%2F%2824-v%29\" = 32.03   (approximately).\r\n" );
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document.write( "====> 24 + v = 32.03*(24 - v)  ====>  v + 32.03v = 32.03*24 - 24  ====>  v = \"744.72%2F%281%2B32.03%29\" = 22.55  (approximately).\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved. The answer is v = 22.55.\r
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\n" ); document.write( "\n" ); document.write( "Check. \"%289%2F24%29%2Aln%28%2824%2B22.55%29%2F%2824-22.55%29%29\" = 1.3. Correct !\r
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