document.write( "Question 1061683: Im having problems with a discussion board question and need help. this is for Math 111 and I am completely lost. the question is as followed:\r
\n" ); document.write( "\n" ); document.write( "If we assume that air resistance is proportional to the square of the velocity, then the time t in seconds required for an object to reach a velocity v in feet per second is given by:\r
\n" ); document.write( "\n" ); document.write( " t=9/24ln 24+v/24-v, 0 ≤ v < 24\r
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\n" ); document.write( "\n" ); document.write( "determine the velocity, to the nearest hundredth foot per second of the object after 1.3 seconds
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Algebra.Com's Answer #676449 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
If we assume that air resistance is proportional to the square of the velocity, then the time t in seconds required for an object to reach a velocity v in feet per second is given by:
\n" ); document.write( "t=9/24ln 24+v/24-v, 0 ≤ v < 24 \r
\n" ); document.write( "\n" ); document.write( "determine the velocity, to the nearest hundredth foot per second of the object after 1.3 seconds
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\n" ); document.write( "Solve::
\n" ); document.write( "1.3 = (9/24)ln(24+v)/(24-v)
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\n" ); document.write( "ln[(24+v)/(24-v)] = 3.467
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\n" ); document.write( "(24+v)/(24-v) = e^3.467
\n" ); document.write( "24+v = 32.03(24-v)
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\n" ); document.write( "24+v = 768.72 - 32.03v
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\n" ); document.write( "33.03v = 744.72
\n" ); document.write( "v = 22.55
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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